math/问题/判断能否被整数n整除.md
2023-11-05 21:09:32 +08:00

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# 判断能否被整数n整除
- 2个位是偶数
- 3各位数之和是3的倍数
- 4末两位数是4的倍数
- 5个位为0和5
- 6各位数之和是3的倍数的偶数
- 7截去个位后减去个位数的2倍的差是7的倍数(可重复操作)
- 8百位以内的数是8的倍数
- 9各位数之和是9的倍数
- 10个位是0
- 11截去个位后减去个位数的差是11的倍数(可重复操作); 各奇数位之和和各偶数位之和的差是11的倍数
- 12同时是3和4的倍数
- 13截尾、4倍大、相加、验和
- 147的偶数倍
- 15同时是3和5的倍数